The first three terms of a sequence are 7, 13, 19…, find the 64th term.

Question

The first three terms of a sequence are 7, 13, 19…, find the 64th term.

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Doris 1 year 2021-09-04T05:33:09+00:00 1 Answers 6 views 0

Answers ( )

    0
    2021-09-04T05:34:34+00:00

    Answer:

    385 is your answer.

    Step-by-step explanation:

    7 – 1

    13 – 2

    19 – 3

    25 – 4

    31 – 5

    37 – 6

    43 – 7

    49 – 8

    55 – 9

    61 – 10

    67 – 11

    73 – 12

    79 – 13

    85 – 14

    91 – 15

    97 – 16

    103 – 17

    109 – 18

    115 – 19

    121 – 20

    127 – 21

    133 – 22

    139 – 23

    145 – 24

    151 – 25

    157 – 26

    163 – 27

    169 – 28

    175 – 29

    181 – 30

    187 – 31

    193 – 32

    199 – 33

    205 – 34

    211 – 35

    217 – 36

    223 – 37

    229 – 38

    235 – 39

    241 – 40

    247 – 41

    253 – 42

    259 – 43

    265 – 44

    271 – 45

    277 – 46

    283 – 47

    289 – 48

    295 – 49

    301 – 50

    307 – 51

    313 – 52

    319 – 53

    325 – 54

    331 – 55

    337 – 56

    343 – 57

    349 – 58

    355 – 59

    361 – 60

    367 – 61

    373 – 62

    379 – 63

    385 – 64

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