The equations y+x^2+6x+8 and y =(x+2) (x+4) both define the same quadratic function. Without graphing, identify the x- and y-intercepts of t

Question

The equations y+x^2+6x+8 and y =(x+2) (x+4) both define the same quadratic function. Without graphing, identify the x- and y-intercepts of the graph. Explain how you know.

please help!

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Hưng Khoa 2 weeks 2021-07-22T17:19:46+00:00 2 Answers 3 views 0

Answers ( )

    0
    2021-07-22T17:20:51+00:00

    Answer:

    x-intercept=

    x=-2

    x=-4

    y-intercept=

    y=8

    Step-by-step explanation:

    0(y)=(x+2) (x+4)

    so we had to substract it to get 0. therefore x intercept is that

    y+x^2+6x+8

    ax^2+bx+c

    c is always y intercept

    0
    2021-07-22T17:20:55+00:00

    Answer:

    we get the  

    x-intercepts setting y=0 and the in the equation

    y-intercept setting x=0 in the equation.

    Step-by-step explanation:

    x-intercepts( y=0)

    0=x^2+6x+8=(x+2)(x+4)

    Hence x=-2 and x=-4 ( We got two x-intercepts)

    y-intercept( x=0)

    y=0^2+6(0)+8=8.

    the y intercept is y=8 ( only is possible to find no more thant one).

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )