The enthalpy of Sodium is 235 calories. The enthalpy Chlorine is 435 calories. The enthalpy of Sodium chloride 670 joules, what is the chang

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The enthalpy of Sodium is 235 calories. The enthalpy Chlorine is 435 calories. The enthalpy of Sodium chloride 670 joules, what is the change in enthalpy for this reaction?

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Ngọc Khuê 4 years 2021-07-13T01:05:20+00:00 1 Answers 38 views 0

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  1. ThanhThu
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    2021-07-13T01:06:20+00:00
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    Answer:

    ΔH = -2446J

    Explanation:

    Based on the reaction:

    2 Na(s) + Cl2(g) → 2NaCl

    We can find the enthalpy of this reaction using Hess’s law:

    The enthalpy of a reaction is equal to the sum of the enthalpy of products times their reaction quotient subtracting the enthalpy of reactants times their reaction quotient. For the reaction of the problem:

    ΔH = 2ΔH(NaCl) – [2ΔH(Na) + ΔHCl2)]

    ΔH(NaCl) = 670J

    ΔH(Na) = 235cal * (4.184J/1cal) = 983J

    ΔHCl2 = 435cal * (4.184J/1cal) = 1820J

    ΔH = 2*670J – [2*983J + 1820J]

    ΔH = 1340J – [3786J]

    ΔH = -2446J

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )