The electric potential, when measured at a point equidistant from two particles that have charges equal in magnitude but of opposite sign, i

Question

The electric potential, when measured at a point equidistant from two particles that have charges equal in magnitude but of opposite sign, isA) equal to the net electric field B) smaller than zero C) equal to zero D) equal to the averages of the two distances times the charge E) larger than zero

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Farah 2 weeks 2021-09-02T06:24:44+00:00 1 Answers 0 views 0

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    2021-09-02T06:26:06+00:00

    Answer:

    C) equal to zero

    Explanation:

    Electric potential is calculated by multiplying constant and charge, then dividing it by distance. The location that we want to measure is equidistant from two particles, mean that the distance from both particles is the same(r2=r1). The charges of the particle have equal strength of magnitude but the opposite sign(q2=-q1). The resultant will be:V = kq/r

    ΔV= V1 + V2= kq1/r1 + kq2/r2

    ΔV= V1 + V2= kq1/r1 + k(-q1)/(r)1

    ΔV= kq1/r1 – kq1/r1

    ΔV=0

    The electric potential equal to zero

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