The distance required to stop a car varies directly as the square of its speed.if 250 feet are required to stop a car traveling 60 miles per

Question

The distance required to stop a car varies directly as the square of its speed.if 250 feet are required to stop a car traveling 60 miles per hour, how many feet are required to stop a car traveling 96miles per hour​

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Mộc Miên 5 months 2021-08-15T01:01:28+00:00 1 Answers 200 views 0

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    2021-08-15T01:02:56+00:00

    Answer:

    640 feet.

    Step-by-step explanation:

    Let d represent the distance required to stop and let s represent the speed of the car.

    The distance required to stop varies directly as the square of its speed. In other words:

    d=ks^2

    Where k is the constant of variation.

    250 feet are required to stop a car traveling 60 miles per hour. Substitute:

    (250)=k(60)^2

    Simplify and solve for k:

    \displaystyle 3600k=250\Rightarrow k=\frac{250}{3600}=\frac{25}{360}=\frac{5}{72}

    So, our equation is:

    \displaystyle d=\frac{5}{72}s^2

    Then the distance required to stop a car traveling 96 miles per hour will be:

    \displaystyle d=\frac{5}{72}(96)^2=\frac{5}{72}(9216)=640\text{ feet}

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