The distance between the lenses in a compound microscope is 18 cm. The focal length of the objective is 1.5 cm. If the microscope is to prov

Question

The distance between the lenses in a compound microscope is 18 cm. The focal length of the objective is 1.5 cm. If the microscope is to provide an angular magnification of -46 when used by a person with a normal near point (25 cm from the eye), what must be the focal length of the eyepiece

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Kiệt Gia 2 months 2021-07-22T11:42:59+00:00 1 Answers 10 views 0

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    2021-07-22T11:44:08+00:00

    Answer:

    The focal length of eye piece is 6.52 cm.

    Explanation:

    Given that,

    Angular Magnification of the microscope M = -46

    the distance between the lens in microscope L= 16 cm

    The focal length of objective f₀ = 1.5 cm

    Normal near point N = 25 cm

    Have to find focal length of eye piece f ₙ =?

    The angular magnification is given by

    M ≈ – (L-fₙ)N/f₀fₙ

    Rearranging for fₙ

    fₙ =L(1 – Mf₀/N)⁺¹

       =18/2.76

    fₙ =  6.52 cm

    The focal length of eye piece is 6.52 cm.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )