The distance AB rounded to the nearest tenth (-2, 1) and (1,-1)

Question

The distance AB rounded to the nearest tenth
(-2, 1) and (1,-1)

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Thu Cúc 3 weeks 2021-08-27T06:24:57+00:00 2 Answers 1 views 0

Answers ( )

    0
    2021-08-27T06:25:59+00:00

    Answer: distance = 13

    Explanation: use distance formula to solve for d.

    0
    2021-08-27T06:26:24+00:00

    Answer:

    it gives you the formula, so all you have to do is plug in the coordinates

    \begin{gathered}d = \sqrt{ {( – 1 + 3)}^{2} + {( – 1 – 1)}^{2} } \\ d = \sqrt{ {(2)}^{2} + {( – 2)}^{2} } \\ d = \sqrt{ 4 + 4 } \\ d = \sqrt{8} \\ d = 2 \sqrt{3} = 3.4641… \\ \\ d = 3.5\end{gathered}

    d=

    (−1+3)

    2

    +(−1−1)

    2

    d=

    (2)

    2

    +(−2)

    2

    d=

    4+4

    d=

    8

    d=2

    3

    =3.4641…

    d=3.5

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )