The diagram below shows a 5.0-kilogram bucket of water being swung in a horizontal circle of 0.70-meter radius at a constant speed of

Question

The diagram below shows a 5.0-kilogram bucket of water being swung in a horizontal circle of 0.70-meter radius
at a constant speed of 2.0 meters per second.
5.0-kg Bucket
0.70 m
The magnitude of the centripetal force on the bucket of water is approximately
1) 5.7 N
2) 14 N
3) 29 N
4) 200 N

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Helga 1 year 2021-09-02T02:45:00+00:00 1 Answers 0 views 0

Answers ( )

  1. Calantha
    0
    2021-09-02T02:46:15+00:00
    Reply

    Answer:

    F = 29 N

    Explanation:

    We have,

    Mass of the bucket of water is 5 kg

    Radius of a horizontal circle is 0.7 m

    Speed of the circle is 2 m/s

    It is required to find the magnitude of centripetal force on the bucket of water. The formula used to find the magnitude of centripetal force is given by :

    [tex]F=\dfrac{mv^2}{r}\\\\F=\dfrac{5\times (2)^2}{0.7}\\\\F=28.57\ N[/tex]

    or

    F = 29 N

    So, the centripetal force on the bucket of water is 29 N.

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