The density of a 25.0% HCl solution (by mass) is 1.05 g/mL, what is the molality of the solution? (MW HCI: 36.46g/mol, H2O: 18.015g/mo

Question

The density of a 25.0% HCl solution (by mass) is 1.05 g/mL, what is the molality of the solution?
(MW HCI: 36.46g/mol, H2O: 18.015g/mol)
a. 9.60 m
b. 6.86 m
c. 7.20 m
d. 9.14 m
e. None of the above

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Edana Edana 5 months 2021-08-11T14:17:24+00:00 1 Answers 16 views 0

Answers ( )

    0
    2021-08-11T14:19:16+00:00

    Answer:

    [HCl] = 14.7M in HCl

    Explanation:

    Definition of Molarity (M) = moles solute / Liters of Solution

    Given 25.0% HCl (aq) => 25g HCl/100g Solution => ? moles HCl/Liter Solution

    Convert 25g HCl to moles = moles solute

    moles HCl => moles HCl = 25g HCl / 18.015g HCl/mole HCl = 1.387732 mole HCl = 1.4 moles HCl (2sig.figs.)

    Determine Liters of Solution as follows:

    Given 25% HCl Solution => 25g HCl/100 g Solution

    100 g Solution = (100 g solution) /  (1.05 g Solution/ml Solution )

    = 95.2381 ml Solution x 1 Liter Solution/1000 ml Solution

    = 0.0952 Liters Solution

    Apply above mole and volume data to definition of mole.

    ∴Molarity = moles solute / Liters solution

    = 1.4 moles solute (HCl)/0.0952 L solution

    = 14.7 Molar in HCl(aq)

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