The decrease of PE for a freely falling object equals its gain in KE, in accord with the conservation of energy. By simple algebra, find an

Question

The decrease of PE for a freely falling object equals its gain in KE, in accord with the conservation of energy. By simple algebra, find an equation for an object’s speed v after falling a vertical distance h. Do this by equating KE to its change of PE.

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Minh Khuê 1 year 2021-09-02T14:34:11+00:00 1 Answers 7 views 0

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    2021-09-02T14:35:49+00:00

    Answer:

    [tex]v = \sqrt{20h} [/tex]

    Explanation:

    The potential energy (PE) we are looking here is gravitational potential energy (GPE).

    GPE= mgh,

    where m is the mass of an object,

    g is the gravitational field strength

    h is the height of the object

    KE= ½mv²,

    where m is the mass and v is the velocity

    loss in GPE= gain in KE

    mgh= ½mv²

    gh= ½v² (divide by m throughout)

    Assuming that the object is on earth, then g= 10N/Kg

    ½v²= 10h (substitute g=10)

    v²= 20h (×2 on both sides)

    v= √20h (square root both sides)

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