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## The decrease of PE for a freely falling object equals its gain in KE, in accord with the conservation of energy. By simple algebra, find an

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The decrease of PE for a freely falling object equals its gain in KE, in accord with the conservation of energy. By simple algebra, find an equation for an object’s speed v after falling a vertical distance h. Do this by equating KE to its change of PE.

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Physics
1 year
2021-09-02T14:34:11+00:00
2021-09-02T14:34:11+00:00 1 Answers
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## Answers ( )

Answer:[tex]v = \sqrt{20h} [/tex]

Explanation:The potential energy (PE) we are looking here is gravitational potential energy (GPE).

GPE= mgh,

where m is the mass of an object,

g is the gravitational field strength

h is the height of the object

KE= ½mv²,

where m is the mass and v is the velocity

loss in GPE= gain in KE

mgh= ½mv²

gh= ½v² (

divide by m throughout)Assuming that the object is on earth, then g= 10N/Kg

½v²= 10h (

substitute g=10)v²= 20h (

×2 on both sides)v= √20h(square root both sides)