The bus travelled at velocity 15 ms-l for 5 minutes before it came to a stop. By using suitable linear equation, calculate the distance the

Question

The bus travelled at velocity 15 ms-l for 5 minutes before it came to a stop. By using suitable linear equation, calculate the distance the bus has travelled.​

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niczorrrr 3 months 2021-07-19T16:24:17+00:00 1 Answers 2 views 0

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    2021-07-19T16:25:32+00:00

    Answer:

    ans: 2250 meters

    Explanation:

    initial velocity (U)= 15 m/s

    final velocity (V) = 0m/s , since need to come in rest

    total time taken (T) = 5 min= 300 seconds

    total distance covered (S)= UT + 1/2 aT^2 ,

    a= acceleration

    S= 15 × 300 + 0.5 ×(0 – 15) × 300

    since a = (V – U)/ T

    S = 4500 – 2250

    S= 2250 m

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