The ball is launched with total initial energy Einitial = mgho. When it reaches the bottom of the hoops, it now has a potential ernergy of P

Question

The ball is launched with total initial energy Einitial = mgho. When it reaches the bottom of the hoops, it now has a potential ernergy of PE mghplat for m. How much kinetic energy must it have at that point? Omgho Omghplat formmgho mghplat form Omgho mghplat for m

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Kim Chi 3 years 2021-08-25T18:17:26+00:00 1 Answers 5 views 0

Answers ( )

  1. ThanhThu
    0
    2021-08-25T18:19:06+00:00
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    Answer:

      K = m g (h₀ – h_plat)

    Explanation:

    Let’s use energy conservation to solve this problem, write the energy at two points of interest

    Initial. Higher

              E_initial = m g h₀

    Final. Lower

              E_end = K + Ep

              E_end = ½ m v² + m g h_plat

    Energy is conserved

              E_initial = E_end

              m g h₀ = K + m g h_plat

              K = m g (h₀ – h_plat)

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