The Atwood machine consists of two masses hanging from the ends of a rope that passes over a pulley. The pulley can be approximated by a uni

Question

The Atwood machine consists of two masses hanging from the ends of a rope that passes over a pulley. The pulley can be approximated by a uniform disk with mass p=7.95 kg and radius p=0.89 m. The hanging masses are L=32.0 kg and R=17.8 kg. Calculate the magnitude of the masses’ acceleration and the tension in the left and right ends of the rope, L and R , respectively.

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Vân Khánh 4 years 2021-08-16T04:14:28+00:00 1 Answers 24 views 0

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  1. linhdan
    0
    2021-08-16T04:16:16+00:00
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    Answer:

    Acceleration(a) = 2.588 m/s²

    TL = 230.784 N

    TR = 220.5 N

    Explanation:

    Given:

    M = 7.95 kg

    mL = 32 kg

    mR = 17.8 kg

    g = 9.8 m/s²

    Find:

    Acceleration(a)

    TL

    TR

    Computation:

    Acceleration(a) = [(mL – mR)g] / [mL + mR + M/2]

    Acceleration(a) = [(32 – 17.8)9.8] / [32 + 17.8 + 7.95/2]

    Acceleration(a) = [139.16] / [53.775]

    Acceleration(a) = 2.588 m/s²

    TL = mL(g-a)

    TL = 32(9.8-2.588)

    TL = 230.784 N

    TR = mR(g+a)

    TR = 17.8(9.8+2.588)

    TR = 220.5 N

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