The acceleration due to gravity at the north pole of Neptune is approximately 10.7m/s2. Neptune has mass 1026kg and radius 25000km and rotat

Question

The acceleration due to gravity at the north pole of Neptune is approximately 10.7m/s2. Neptune has mass 1026kg and radius 25000km and rotates once around its axis in a time of about 16h.

Part A

What is the gravitational force on an object of mass 5.5kg at the north pole of Neptune?

Part B

What is the apparent weight of this same object at the Neptune’s equator? (Note that Neptune

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Ladonna 2 months 2021-07-30T00:48:30+00:00 1 Answers 18 views 0

Answers ( )

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    2021-07-30T00:50:29+00:00

    Answer:

    (A) Force on the object will be 58.85 N

    (B) Apparent weight will be equal to 57.21 N

    Explanation:

    We have given mass of Neptune m = 1026 kg

    Radius R = 25000 Km

    Time period = 16 hour

    We know that 1 hour = 3600 sec

    So 16 hour = 16×86400 = 57600 sec

    Acceleration due to gravity at north pole of Neptune g=10.7m/sec^2

    (A) Mass of the object m = 5.5 kg

    So gravitational force on the object F_g=mg=5.5\times 10.7=58.85N

    (B) Velocity will be equal to v=\frac{2\pi R}{T}=\frac{2\times 3.14\times25000\times 1000}{57600}=2725.694m/sec

    Apparent weight of the object will be equal to w=f_g-\frac{mv^2}{r}

    W=58.85-\frac{5.5\times (2725.694)^2}{25000\times 1000}=57.21N

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