The 3rd bright fringe of a double slit interference pattern is 30.0 cm above the central bright fringe. If the angle from the horizontal to

Question

The 3rd bright fringe of a double slit interference pattern is 30.0 cm above the central bright fringe. If the angle from the horizontal to this 3rd bright fringe is 12.0 degrees, what is the distance (in meters) between the double slits and the viewing screen

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Thu Thảo 4 years 2021-07-26T23:19:52+00:00 1 Answers 66 views 0

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  1. Amity
    0
    2021-07-26T23:21:14+00:00
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    Answer:

    Explanation:

    12 degree = (π / 180) x 12 radian

    = .2093 radian

    position of third bright fringe = 3λ D/ d where λ is wave length of light , D is screen distance and d is slit separation

    given

    3λ D/ d = 30 x 10⁻²

    angular separation

    3λ / d = .2093

    from the two equation

    .2093 D= 30 x 10⁻²

    D = 30 x 10⁻² / .2093

    = 1.43 m

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