Ten high-technology batteries are tested for 200 hours each. One failed at 20 hours; another failed at 140 hours; all others completed the t

Question

Ten high-technology batteries are tested for 200 hours each. One failed at 20 hours; another failed at 140 hours; all others completed the test. FR(%) is __________ and MTBF is __________.

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Nho 5 years 2021-08-10T14:12:23+00:00 1 Answers 8 views 0

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  1. dangkhoa
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    2021-08-10T14:13:36+00:00
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    Answer:

    Failure rate   = 20%

    MTBF = 880 hours

    Explanation:

    given data

    batteries = 10

    tested = 200 hours

    one failed = 20 hours

    another fail at =  140 hours

    solution

    we know that Mean Time between Failures is express as = (Total up time) ÷  (number of breakdowns)    ………………..1

    so here Total up time will be

    Total up time = 200 × 10

    Total up time = 2000

    and here

    Number of breakdown = 1 at 20 hour and another at 140 hour = 2

    so it will be  = (Total up time) ÷ (number of breakdowns)      …….2

    =  \frac{2000}{2}   =  1000  

    so here gap between occurrences is

    gap between occurrences=  140 – 20

    gap between occurrences = 120 hour

    and

    MTBF  will be

    MTBF = 1000 – 120

    MTBF = 880 hours  

    and

    Failure rate (FR)  will be

    Failure rate (FR) =  1 ÷ MTBF    …………….3

    Failure rate (FR) = R÷T     ………………….4

    as here R is the number of failures and T is total time

    so Failure rate (FR)  = 20%

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