factorise \: \\ \\ r {}^{2} - 10r + 21 ​

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factorise \: \\ \\ r {}^{2} - 10r + 21
​

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Gerda 6 months 2021-08-04T11:43:22+00:00 1 Answers 7 views 0

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  1. ThanhThu
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    2021-08-04T11:45:00+00:00
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    \implies {\blue {\boxed {\boxed {\purple {\sf { \: (r - 7)(r - 3) }}}}}}

    \sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}

    {r}^{2} - 10r + 21

    = {r}^{2} - 7r - 3r + 21

    Taking r as common from first two terms and 3 from last two terms, we have

    = r(r - 7) - 3(r - 7)

    Taking the factor (x-7) as common,

    = (r - 7)(r - 3)

    \bold{ \green{ \star{ \orange{Mystique35}}}}⋆

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )