Suppose y varies inversely with x, and y = 18 when x = 12. What is the value of x when y = 24? NO LINKS OR ANSWERING YOU DON’T KNOW? <

Question

Suppose y varies inversely with x, and y = 18 when x = 12. What is the value of x when y = 24? NO LINKS OR ANSWERING YOU DON’T KNOW?

a. 24
b. 9
c. 12
d. 18​

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Ngọc Hoa 3 years 2021-07-28T12:26:24+00:00 2 Answers 8 views 0

Answers ( )

  1. thienan
    0
    2021-07-28T12:28:16+00:00
    Reply

    Answer:

    B

    Step-by-step explanation:

    Given that y varies inversely with x then the equation relating them is

    y = \frac{k}{x} ← k is the constant of variation

    To find k use the condition y = 18 when x = 12 , then

    18 = \frac{k}{12} ( multiply both sides by 12 )

    216 = k

    y = \frac{216}{x} ← equation of variation

    When y = 24 , then

    24 = \frac{216}{x} ( multiply both sides by x )

    24x = 216 ( divide both sides by 24 )

    x = 9

  2. Edana
    0
    2021-07-28T12:28:21+00:00
    Reply

    Answer:

    B. 9

    Step-by-step explanation:

    We are given that y varies inversely with x. Recall that inverse variation has the form:

    \displaystyle y=\frac{k}{x}

    Where k is the constant of variation.

    We are given that y = 18 when x = 12. Hence:

    \displaystyle (18)=\frac{k}{(12)}

    Solve for k. Multiply both sides by 12:

    k=12(18)=216

    Thus, our equation is:

    \displaystyle y=\frac{216}{x}

    We want to find x when y = 24. Substitute:

    \displaystyle \frac{24}{1}=\frac{216}{x}

    Cross-multiply:

    24x=216

    Divide both sides by 24. Hence:

    x=9

    Our answer is B.

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