Suppose there is a CD that is rotating at a rate of 450 rpm. Suppose that there is a speck of dust that is 4 cm away from the center of the

Question

Suppose there is a CD that is rotating at a rate of 450 rpm. Suppose that there is a speck of dust that is 4 cm away from the center of the CD. What is the total distance traveled by that speck of dust in 2 minutes

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MichaelMet 1 week 2021-07-22T11:02:21+00:00 1 Answers 1 views 0

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    2021-07-22T11:03:52+00:00

    Answer:

    d=226.2m

    Step-by-step explanation:

    From the question we are told that:

    Rotational Speed N =450rpm

    Time T=2min=>120sec

    Radius r=4cm=>0.04m

    Generally the equation for Distance Traveled is mathematically given by

     d=\omega*2\pi r*T

     d=450*2*\pi*0.04*2

     d=226.2m

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