Suppose there are three balls in a box. On one of the balls is the number 1, on another is the number 2, and on the third is the number 3. Y

Question

Suppose there are three balls in a box. On one of the balls is the number 1, on another is the number 2, and on the third is the number 3. You select two balls at random and without replacement from the box and note the two numbers observed. The sample space S consists of the three equally likely outcomes {(1, 2), (1, 3), (2, 3)} (disregarding order). Let X be the sum of the two balls selected. What is the mean of X

in progress 0
Delwyn 4 days 2021-07-22T22:53:46+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-07-22T22:55:29+00:00

    Step-by-step explanation:

    a) X is a discrete uniform distribution. As the number of outcomes is only 3.

    b) sum is at least 4

    X ≥ 4——–

    i.e  (1,3) or (2,3)

    probability of X ≥ 4 is 2/3

    2/3= 0.667

    66.7 % is the probability of the outcome to have  a sum at least 4.

    c) The 3 likely outcome of X

    (1,2) where X ; 1+2=3

    (1,3) where X ; 1+3=4

    (2,3) where X ;  2+3=5

    Mean = 3+4+5/ 3

    Mean = 4

    Feel free to ask any uncleared step

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )