Suppose the tourist in question 1 instead threw the rockwith an initial velocity of 8.0m/s[down]determine the velocity and the displacement

Question

Suppose the tourist in question 1 instead threw the rockwith an initial velocity of 8.0m/s[down]determine the velocity and the displacement of the rock at4.0s[remember thev is down and must become a 8.0 m/s]

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Philomena 5 years 2021-08-03T05:31:56+00:00 1 Answers 141 views 0

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  1. Euphemia
    0
    2021-08-03T05:33:13+00:00
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    Answer:

    The velocity of the rock is 47.24 m/s

    The displacement of the rock is 110.48 m

    Explanation:

    The initial velocity u = 8.0 m/s

    time t = 4.0 s

    Using

    v = u + gt

    where v is the final velocity of the rock after 4.0 s

    u is the initial speed = 8 m/s

    g is acceleration due to gravity = 9.81 m/s

    t is the time = 4.0 s

    substituting, we have

    v = 8 + (9.81*4)

    v = 8 + 39.24 = 47.24 m/s

    Also, using

    s = ut + \frac{1}{2} gt^{2}

    where

    s is the distance that the stone fell

    t is the time = 4.0 s

    g is the acceleration due to gravity = 9.81 m/s^2

    substituting values, we have

    s = (8 * 4) + (\frac{1}{2}*9.81*4^{2})

    s = 32 + 78.48

    s = 110.48 m

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