Suppose that 20° of boys opted for mathematics and 40% of girls opted for mathematics. What is the probability that a student opted for math

Question

Suppose that 20° of boys opted for mathematics and 40% of girls opted for mathematics. What is the probability that a student opted for mathematics if half of the class is girls?​

in progress 0
Latifah 3 years 2021-07-26T00:14:11+00:00 1 Answers 4 views 0

Answers ( )

  1. yenoanh
    0
    2021-07-26T00:15:35+00:00
    Reply

    Answer: 30%

    Step-by-step explanation:

    Let A be the probability of a student opting for mathematics – it consists of either boy opting for mathematics or girl opting for mathematics. As there is “or” we need to sum these probabilities.

    P(A) = P(B)* P(M|G) + P(G)*P(M|G)

    P(A) = \frac{1}{2} * \frac{20}{100} + \frac{1}{2} * \frac{40}{100}

    P(A) = 3/10 = 0.3

    => 30%

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )