Suppose an individual is lying on his stomach with sheets of paper stacked on his back. If each sheet of paper has a mass of 0.00350 kg and

Question

Suppose an individual is lying on his stomach with sheets of paper stacked on his back. If each sheet of paper has a mass of 0.00350 kg and is the standard letter size of 8.5 in by 11 in ( 0.216 m by 0.279 m ), how many sheets must be stacked to produce a pressure on his back equal to atmospheric pressure (roughly 101325 Pa )

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Nem 4 days 2021-07-22T21:13:31+00:00 1 Answers 2 views 0

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    2021-07-22T21:15:30+00:00

    Answer:

    N = 177843 sheets

    Explanation:

    We are given;

    Mass;m = 0.0035 kg

    Pressure; p = 101325 pa = 101325 N/m²

    L = 0.279m

    W = 0.216m

    The weight of N sheets is N(mg)

    Where;

    m is the mass of one sheet

    N is number of sheets

    g is the acceleration due to gravity.

    The pressure equals weight divided by the area on which the weight presses:

    Thus,

    p= F/A = Nmg/(L•W)

    Therefore, making N the subject;

    N = pLW/(mg)

    N = 101325 x 0.279 x 0.216/ (0.0035 x 9.81)

    N = 177843

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