Suppose a speck of dust in an electrostatic precipitator has 1×1012 protons in it and has a net charge of −5.2 nC (a very large charge for a

Question

Suppose a speck of dust in an electrostatic precipitator has 1×1012 protons in it and has a net charge of −5.2 nC (a very large charge for a small speck). How many electrons does it have?

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Nem 3 years 2021-08-27T17:09:52+00:00 1 Answers 281 views 0

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  1. Euphemia
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    2021-08-27T17:10:59+00:00
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    Explanation:

    The given data is as follows.

             q_{net} = -5.2 nC = -5.2 \times 10^{-9} C  

              charge on an electron (e) = 1.6 \times 10^{-19} C

    Formula to calculate number of electrons is as follows.

                   Q = ne

    or,           n = \frac{Q}{e}

    Putting the given values into the above formula as follows.

                    n = \frac{Q}{e}

                       = \frac{-5.2 \times 10^{-9} C}{1.6 \times 10^{-19} C}

                       = -3.25 \times 10^{10} C

    We know that when total charge is zero then number of protons is equal to the number of electrons.

    That is,      n_{p} = n_{e}

    So, total number of electrons present are as follows.

                  n_{e} = 1 \times 10^{12} + 3.25 \times 10^{10}

                              = 103.25 \times 10^{10} C

    Therefore, we can conclude that given speck of dust has 103.25 \times 10^{10} electrons.

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