Suppose a NASCAR race car rounds one end of the Martinsville Speedway. This end of the track is a turn with a radius of approximately 57.0 m

Question

Suppose a NASCAR race car rounds one end of the Martinsville Speedway. This end of the track is a turn with a radius of approximately 57.0 m . If the track is completely flat and the race car is traveling at a constant 26.5 m/s (about 59 mph ) around the turn, what is the race car’s centripetal (radial) acceleration

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Diễm Kiều 5 months 2021-08-23T11:39:37+00:00 1 Answers 12 views 0

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    2021-08-23T11:41:32+00:00

    Answer:

    The centripetal acceleration of the car will be 12.32 m/s² .

    Explanation:

    Given that

    radius ,R= 57 m

    Velocity , V=26.5 m/s

    We know that centripetal acceleration given as follows

    a_c=\dfrac{V^2}{R}

    Now by putting the values in the above equation we get

    a_c=\dfrac{26.5^2}{57}=12.32\ m/s^2

    Therefore the centripetal acceleration of the car will be 12.32 m/s² .

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