## Suppose 1 kg each of water (4.19 J/(g ⋅∘C)), brick (0.90 J/(g⋅∘C)), iron (0.46 J/(g⋅∘C)), and olive oil (1.79 J/(g⋅∘C)) were held at the sam

Question

Suppose 1 kg each of water (4.19 J/(g ⋅∘C)), brick (0.90 J/(g⋅∘C)), iron (0.46 J/(g⋅∘C)), and olive oil (1.79 J/(g⋅∘C)) were held at the same initial temperature and heated for an equivalent amount of time. Indicate their relative final temperatures from lowest (left) to highest (right). Assume no heat is lost to the surroundings. You can use the Intro tab of the PhET to help visualize the temperature changes. (Assume that the mas of the water, iron, and olive oil is 1 kg each and that the mass of the brick is 0.5 kg.)

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1 week 2021-07-22T22:25:41+00:00 1 Answers 4 views 0

Explanation:

For rise in temperature due to addition of heat, the formula is as follows

Q = m s Δ t , Q is amount of heat added , m is mass , s is specific heat and

Δ t  is rise in temperature .

Δ t = Q / ms

For water , iron , olive oil mass is 1 kg

So

for water,

Δ t = Q / 4.19

for iron,

Δ t = Q / .46

for olive oil,

Δ t = Q / 1.79

For brick

Δ t = Q / .5 x .9

= Q / .45

Lower the denominator , higher the value.

So

Q / 4.19 < Q / 1.79 <Q / .46 <Q / .45

Tfinal (water)<Tfinal (olive oil)Tfinal (iron)Tfinal (brick )