Sunlight, with an intensity of 637 W / m 2 , strikes a flat collecting surface perpendicularly and is totally absorbed. The area of the

Question

Sunlight, with an intensity of 637 W / m 2 , strikes a flat collecting surface perpendicularly and is totally absorbed. The area of the surface is 8.33 m 2 . What is the force F in micronewtons that acts on the surface due to the sunlight?

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Ngọc Diệp 2 weeks 2021-07-22T06:27:20+00:00 1 Answers 1 views 0

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    2021-07-22T06:28:32+00:00

    Answer:

    Force of 17.6 micrometer is acting on the surface due to the sunlight.

    Explanation:

    Given that,

    Intensity of sunlight is I=637\ W/m^2

    It strikes a flat collecting surface perpendicularly and is totally absorbed. The area of the surface is A=8.33\ m^2

    P=F\times v

    So, force is given by :

    F=\dfrac{IA}{c}  

    c is speed of light

    F=\dfrac{637\times 8.33}{3\times 10^8}\\\\F=17.6\ \mu N

    So, force of 17.6 micrometer is acting on the surface due to the sunlight.

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