Someone plans to float a small, totally absorbing sphere 0.518 m above an isotropic point source of light, so that the upward radiation forc

Question

Someone plans to float a small, totally absorbing sphere 0.518 m above an isotropic point source of light, so that the upward radiation force from the light matches the downward gravitational force on the sphere. The sphere’s density is 22.2 g/cm3, and its radius is 2.12 mm. (a) What power would be required of the light source

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Nho 3 months 2021-07-29T14:11:56+00:00 1 Answers 2 views 0

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    2021-07-29T14:13:16+00:00

    Answer:

    Explanation:

    From the question we are told that

      The  height is  h  =  0.518 \  m

        The  sphere density is  \rho =  22.2g/cm^3 =  \frac{22.2 }{1000}  *  1*10^{6} =  22200 kg/m^3

        The  radius is  r =  2.12 \  mm =0.00212 \ m

    Generally the power required  is mathematically represented as

       P  =  \frac{16 *  \pi *  \rho *  r *  g *  h^2 * c }{3}

    substituting values  

        P  =  \frac{16 * 3.142 *  22200 *  0.00212 *  9.8 *  0.518^2 *  3.0*10^{8}}{ 3}

       P  = 6.22*10^{11} \  W

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