Solve the quadratic equation by factoring. 4x^2-20x+28=3

Question

Solve the quadratic equation by factoring. 4x^2-20x+28=3

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Hưng Khoa 3 months 2021-07-25T02:17:27+00:00 2 Answers 6 views 0

Answers ( )

    0
    2021-07-25T02:18:29+00:00

    Answer is definitely x=52x=52

    0
    2021-07-25T02:19:04+00:00

    Answer:

    X=5/2

    Step-by-step explanation:

    4×2−20x+28=34×2-20x+28=3

    Move all terms to the left side of the equation and simplify.

    Tap for more steps…

    4×2−20x+25=04×2-20x+25=0

    Use the quadratic formula to find the solutions.

    −b±√b2−4(ac)2a-b±b2-4(ac)2a

    Substitute the values a=4a=4, b=−20b=-20, and c=25c=25 into the quadratic formula and solve for xx.

    20±√(−20)2−4⋅(4⋅25)2⋅420±(-20)2-4⋅(4⋅25)2⋅4

    Simplify.

    Tap for more steps…

    x=52x=52

    The final answer is the combination of both solutions.

    x=52x=52 Double roots

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )