Small quantities of hydrogen gas can be prepared in the lab by addition of hydrochloric acid to zinc. The gas is typically collected over w

Question

Small quantities of hydrogen gas can be prepared in the lab by addition of hydrochloric acid to zinc. The gas is typically collected over water. What volume of hydrogen can be collected from 0.625g Zn

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Kiệt Gia 3 years 2021-07-27T22:10:02+00:00 1 Answers 51 views 0

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  1. trungdung22
    0
    2021-07-27T22:11:36+00:00
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    Answer:

    0.214 L

    Explanation:

    Step 1: Write the balanced equation

    This is a single displacement reaction.

    Zn(s) + 2 HCl(aq) ⇒ ZnCl₂(aq) + H₂(g)

    Step 2: Calculate the moles corresponding to 0.625 g of Zn

    The molar mass of Zn is 65.38 g/mol.

    0.625 g × 1 mol/65.38 g = 9.56 × 10⁻³ mol

    Step 3: Calculate the moles of H₂ produced from 9.56 × 10⁻³ moles of Zn

    The molar ratio of Zn to H₂ is 1:1. The moles of H₂ produced are 1/1 × 9.56 × 10⁻³ mol = 9.56 × 10⁻³ mol.

    Step 4: Calculate the volume occupied by 9.56 × 10⁻³ moles of hydrogen

    Assuming standard pressure and temperature, 1 mole of hydrogen occupies 22.4 L.

    9.56 × 10⁻³ mol × 22.4 L/1 mol = 0.214 L

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