Sherbrooke, Quebec is 210 miles from Boston, MA. A train leaves Boston at noon and arrives in Sherbrooke at 4:40 PM. On the return trip to B

Question

Sherbrooke, Quebec is 210 miles from Boston, MA. A train leaves Boston at noon and arrives in Sherbrooke at 4:40 PM. On the return trip to Boston, the train travels 50.4 mph. How many times greater (or less) is the train’s speed on the return trip to Boston than on the trip to Sherbrooke?

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Nick 3 years 2021-08-30T15:59:10+00:00 2 Answers 26 views 0

Answers ( )

  1. kiet
    0
    2021-08-30T16:00:10+00:00
    Reply

    9514 1404 393

    Answer:

      1.12 times as great

    Step-by-step explanation:

    The speed from Boston is …

      (210 mi)/(4 2/3 h) = 45 mi/h

    Then the speed to Boston is …

      50.4/45 = 1.12 . . . times as great

    __

    The speed on the return trip is 1.12 times as great, or 12% greater than on the trip to Sherbrooke.

  2. thuthuy
    0
    2021-08-30T16:00:24+00:00
    Reply

    9514 1404 393


    Answer:


     1.12 times as great


    Step-by-step explanation:


    The speed from Boston is …

      (210 mi)/(4 2/3 h) = 45 mi/h


    Then the speed to Boston is …

      50.4/45 = 1.12 . . . times as great


    __


    The speed on the return trip is 1.12 times as great, or 12% greater than on the trip to Sherbrooke.

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