Say you want to make a sling by swinging a mass M of 1.7 kg in a horizontal circle of radius 0.048 m, using a string of length 0.048 m. You

Question

Say you want to make a sling by swinging a mass M of 1.7 kg in a horizontal circle of radius 0.048 m, using a string of length 0.048 m. You wish the mass to have a kinetic energy of 14.0 Joules when released. How strong will the string need to be

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Yến Oanh 6 months 2021-07-31T13:06:09+00:00 1 Answers 5 views 0

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    2021-07-31T13:08:07+00:00

    Answer:

    Tension in the string is equal to 58.33 N ( this will be the strength of the string )

    Explanation:

    We have given mass m = 1.7 kg

    radius of the circle r = 0.48 mF=\frac{mv^2}{r}=\frac{1.7\times 4.05^2}{0.48}=58.33N

    Kinetic energy is given 14 J

    Kinetic energy is equal to KE=\frac{1}{2}mv^2

    So \frac{1}{2}\times 1.7\times v^2=14

    v^2=16.47

    v = 4.05 m/sec

    Centripetal force is equal to F=\frac{mv^2}{r}=\frac{1.7\times 4.05^2}{0.48}=58.33N

    So tension in the string will be equal to 58.33 N ( this will be the strength of the string )

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