Rectangle HYGT has a perimeter of 170 inches. If the length is 10x – 7 and the width is 6x + 12, how wide is the rectangle?

Question

Rectangle HYGT has a perimeter of 170 inches. If the length is 10x – 7
and the width is 6x + 12, how wide is the rectangle?

in progress 0
Đan Thu 3 weeks 2021-08-23T23:26:17+00:00 1 Answers 1 views 0

Answers ( )

    0
    2021-08-23T23:27:17+00:00

    Answer:

    The wide of the rectangle = 42 inches

    The  length of the rectangle = 43 inches

    Step-by-step explanation:

    Step(i):-

    Given that the length of the rectangle = 10x-7

    Given that the width of the rectangle = 6x +12

    The perimeter of the rectangle = 2(length + width)

    Given that the perimeter of the rectangle = 170

    Step(ii):-

        2(length + width) = 170

            length + width = 85

            10x-7 +6x +12 =85

              16x +5 = 85

               16x = 85-5 = 80

                 x =    \frac{80}{16}

                 x = 5

    Final answer:-

    The  length of the rectangle = 10(5)-7 = 50-7 = 43

    The wide of the rectangle = 6x +12 = 6(5) + 12 = 30+12 =42

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )