QUESTION 1 A 2.5-g copper penny is given a charge of 4.0×10-9 C. If no more than one electron is removed from an atom, what percent of the a

QUESTION 1 A 2.5-g copper penny is given a charge of 4.0×10-9 C. If no more than one electron is removed from an atom, what percent of the atoms are ionized by this charging process

0 thoughts on “QUESTION 1 A 2.5-g copper penny is given a charge of 4.0×10-9 C. If no more than one electron is removed from an atom, what percent of the a”

  1. Answer:

    [tex]\%X=2.34*10^{-14}\%[/tex]

    Explanation:

    From the question we are told that:

    Mass [tex]M=2.5g[/tex]

    Charge [tex]q=4*0*10^{-9}[/tex]

    Generally the equation for Total number of Atoms in Penny is mathematically given by

     [tex]T_a=\frac{Mass}{atomic weight}*1mole[/tex]

     [tex]T_a=\frac{2.5}{63.6}*6.02*10^{23}[/tex]

     [tex]T_a=2.34*10^{27}atoms[/tex]

    Since Number of electrons in a penny is

     [tex]e =nT_a[/tex]

     [tex]e=29*2.34*10^{27}[/tex]

     [tex]e=6.86*10^{23}[/tex]

    Therefore

    The percentage of the atoms are ionized by this charging process is given as

     [tex]\%X=\frac{T_a}{e}[/tex]

     [tex]\%X=\frac{2.34*10^{27}}{6.86*10^{23}}[/tex]

     [tex]\%X=2.34*10^{-14}\%[/tex]

    Reply

Leave a Comment