Public television station KQED in San Francisco broadcasts a sinusoidal radio signal at a power of 777 kW. Assume that the wave spreads out

Question

Public television station KQED in San Francisco broadcasts a sinusoidal radio signal at a power of 777 kW. Assume that the wave spreads out uniformly into a hemisphere above the ground.
A) At a home 5.50km away from the antenna, what average pressure does this wave exert on a totally reflecting surface? answer in PA units
B) At a home 5.50km away from the antenna, what are the amplitudes of the electric and magnetic fields of the wave? answer in N/C, T
C) At a home 5.50km away from the antenna, what is the average density of the energy this wave carries? answer in J/m^3
D) For the energy density in part (c), what percentage is due to the electric field?
E) For the energy density in part (c), what percentage is due to the magnetic field?

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Thái Dương 6 months 2021-07-30T04:15:33+00:00 1 Answers 4 views 0

Answers ( )

    0
    2021-07-30T04:16:46+00:00

    Answer:

    A. Using

    I= P/ A

    So = P/ 2π R²

    So=777E3 watt/ 2*πx (²5.5E3m)

    4.3*10^ -3W/m²

    So pressure= 2I/c

    =2* 4.3*10^ -3W/m²/ 3*10^ 8

    2.7*10^-11p.a

    B.

    Using Emax= √2I/Eoc

    So

    √ 2*4.3*10^-3/8.8E-12*3*10^8

    = 5.48V/m

    So

    Bmax= Emax/c

    5.58/3E8

    = 1.83*10-9T

    D.average density is given by

    = Eo(Emax/√2)²

    = 8.85E-12(5.48/√2)²

    1.3*10^10W/m²

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