Positive charge Q is placed on a conducting spherical shell with inner radius R1 and outer radius R2. A particle with charge q is placed a

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Positive charge Q is placed on a conducting spherical shell with inner radius R1 and outer radius R2. A particle with charge q is placed at the center of the cavity. The net charge on the inner surface of the conducting shell is

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Kiệt Gia 3 years 2021-08-26T04:43:50+00:00 1 Answers 23 views 0

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    2021-08-26T04:45:09+00:00

    Answer: in this question, the only charge in the cavity is Q. Inside the conducting spherical shell, the electric field is zero.

    While outside the shell, the electric field is given by: k(q + Q)/r²

    Where;

    K= is a constant which is given as, 8.99 x 10^9 N m² / C².

    Q= source charge which creates the electric field

    q= is the test charge which is used to measure the strength of the electric field at a given location.

    r= is the radius

    Explanation: Inside the conducting spherical shell, the electric field is zero since the Electric field vanishes everywhere inside the volume of a good conductor.

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