## Points A, B, C, and D are at the corners of a square area in an electric field, with B adjacent to A and C diagonally across from A. The pot

Question

Points A, B, C, and D are at the corners of a square area in an electric field, with B adjacent to A and C diagonally across from A. The potential difference between A and C is the negative of that between A and B and the same as that between B and D. Part B What is the potential difference between C and D? Delta V_CD = Delta V_AB Delta V_CD = -Delta V_AB Delta V_CD = -2 Delta V_AB Delta V_CD = 0 Part C What is the potential difference between A and D? Delta V_CAD = Delta V_AB Delta V_AD = -2 Delta V_AB Delta V_AD = Delta V_AB Delta V_AD = 0

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2 weeks 2021-09-03T13:25:42+00:00 1 Answers 0 views 0

## Answers ( )

1. Answer:

b)    V_CD = – V_AB
,  c)      V_AD = -2 V_AB

Explanation:

b) In this exercise of potential differences they indicate that the diagonal potential is the negative of the leg potential

V_AC = – V_AB

V_BD = – V_CD

Thus

V_CD = V_AC

Finally

V_CD = – V_AB

c) The potential is a scalar quantity so it can be added algebraically, they give us the condition

V_AC = -V_AB

V_AB + V_BC = – V_AB

V_BC = – 2 V_AB

For the other triangle

V_BD = V_AC

V_AB + V_AD =  V_AC

We replace

V_AB + V_AD =  – V_AB

V_AD = -2 V_AB