Points A, B, C, and D are at the corners of a square area in an electric field, with B adjacent to A and C diagonally across from A. The pot

Question

Points A, B, C, and D are at the corners of a square area in an electric field, with B adjacent to A and C diagonally across from A. The potential difference between A and C is the negative of that between A and B and the same as that between B and D. Part B What is the potential difference between C and D? Delta V_CD = Delta V_AB Delta V_CD = -Delta V_AB Delta V_CD = -2 Delta V_AB Delta V_CD = 0 Part C What is the potential difference between A and D? Delta V_CAD = Delta V_AB Delta V_AD = -2 Delta V_AB Delta V_AD = Delta V_AB Delta V_AD = 0

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Diễm Thu 2 weeks 2021-09-03T13:25:42+00:00 1 Answers 0 views 0

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    2021-09-03T13:27:15+00:00

    Answer:

    b)    V_CD = – V_AB
    ,  c)      V_AD = -2 V_AB

    Explanation:

    b) In this exercise of potential differences they indicate that the diagonal potential is the negative of the leg potential

          V_AC = – V_AB

         V_BD = – V_CD

    Thus

             V_CD = V_AC

    Finally

               V_CD = – V_AB

    c) The potential is a scalar quantity so it can be added algebraically, they give us the condition

              V_AC = -V_AB

              V_AB + V_BC = – V_AB

              V_BC = – 2 V_AB

    For the other triangle

              V_BD = V_AC

              V_AB + V_AD =  V_AC

    We replace

              V_AB + V_AD =  – V_AB

              V_AD = -2 V_AB

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )