Pls help A car starts from rest and gains a velocity of 20m/s in 10 seconds calculate its acceleration and the distance covered by it in thi

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Pls help A car starts from rest and gains a velocity of 20m/s in 10 seconds calculate its acceleration and the distance covered by it in this time

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Cherry 3 years 2021-08-09T14:19:01+00:00 1 Answers 19 views 0

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  1. phucdien
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    2021-08-09T14:20:47+00:00
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    Answer:

    \boxed{\sf Acceleration \ (a) = 2 \ m/s^{2}}

    \boxed{\sf Distance \ covered \ (s) = 100 \ m}

    Given:

    Initial velocity (u) = 0 m/s

    Final velocity (v) = 20 m/s

    Time taken (t) = 10 sec

    To Find:

    (i) Acceleration (a)

    (ii) Distance covered (s)

    Explanation:

    \sf (i) \ From \ 1^{st} \ equation \ of \ motion:

    \sf \implies v = u + at

    \sf \implies 20 = 0 + a(10)

    \sf \implies 10a = 20

    \sf \implies \frac{10a}{10} = \frac{20}{10}

    \sf \implies a = 2 \: m/ {s}^{2}

    \sf (ii) \ From \ 2^{nd} \ equation \ of \ motion:

    \sf \implies s = ut + \frac{1}{2} a {t}^{2}

    \sf \implies s = (0)(10) + \frac{1}{2} \times 2 \times {(10)}^{2}

    \sf \implies s = \frac{1}{ \cancel{2}} \times \cancel{2} \times {(10)}^{2}

    \sf \implies s = {10}^{2}

    \sf \implies s = 100 \: m

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