please only reply if you know the answer! What is the maximum number of moles of NaCl that can be produced from the reaction of 5.6 mol Na a

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please only reply if you know the answer! What is the maximum number of moles of NaCl that can be produced from the reaction of 5.6 mol Na and 4.7 mol CI2?

2Na + Cl2 —> NaCl

What is the limiting reactant?

What is the excess reactant?

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Gerda 3 years 2021-08-22T13:35:59+00:00 1 Answers 52 views 0

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  1. Adela
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    2021-08-22T13:37:07+00:00
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    Answer:The ratio of Cl2 to NaCl is 1:2, so for every mole of Cl2 that reacts, two moles of NaCl will be produced. 0.35458 × 2 = 0.70916 moles of NaCl.

    Explanation:The reaction will stop when all of the limiting reactant is consumed. □ The only … Using the equation: 2Na + Cl. 2. → 2NaCl … 6.70 g Na. 1 mol Na. 22.99 g Na. 0.293 mol Na. X. = 3.20 g Cl. 2. 1 mol Cl2. 70.9 g Cl. 2 … 58.44 g NaCl. 1 mol NaCl.

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