PLEASE HELP! The specific heat of octane, C8H18(l), is 2.22 J/(g⋅K). How much heat is needed to raise the temperature of 76.0 g

Question

PLEASE HELP!
The specific heat of octane, C8H18(l), is 2.22 J/(g⋅K).
How much heat is needed to raise the temperature of 76.0 g of octane from 10.6 ∘C to 26.0 ∘C?
Express your answer in joules to three significant figures.

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Tài Đức 6 months 2021-07-31T04:07:00+00:00 2 Answers 256 views 0

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    0
    2021-07-31T04:08:01+00:00

    Answer:

    Q = 2.60 • 10^{3} J

    Explanation:

    Our specific heat capacity equation is:

    Q = mC∆T

    Q is the energy in joules.

    m is the mass of the substance.

    ∆T is the temperature chance.

    Let’s plug in what we know.

    • We have 76.0 g of octane
    • The specific heat capacity of octane is 2.22 J/(g•K)
    • The temperature increases from 10.6º to 26.0º (a 15.4º increase)

    Q = 76.0(2.22)(15.4)

    Multiply.

    Q = 2598.288

    We want three significant figures.

    Q = 2.60 • 10^{3}

    or

    Q = 2590 J

    Hope this helps!

    0
    2021-07-31T04:08:35+00:00

    Answer:6,985.008

    Explanation:

    so the hear formula is mass times specific heat times change in temperature (kelvin) so what i did was got the change in temperature (41.4 K) and multiplied that times 2.22 J/(g•K)and multiplied that by 76 grams of Octane to get the Answer (not in scientific notation)

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