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## PLEASE HELP! The specific heat of octane, C8H18(l), is 2.22 J/(g⋅K). How much heat is needed to raise the temperature of 76.0 g

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PLEASE HELP!

The specific heat of octane, C8H18(l), is 2.22 J/(g⋅K).

How much heat is needed to raise the temperature of 76.0 g of octane from 10.6 ∘C to 26.0 ∘C?

Express your answer in joules to three significant figures.

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Chemistry
6 months
2021-07-31T04:07:00+00:00
2021-07-31T04:07:00+00:00 2 Answers
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## Answers ( )

Answer:Q = 2.60 • J

Explanation:Our specific heat capacity equation is:

Q = mC∆T

Q is the energy in joules.

m is the mass of the substance.

∆T is the temperature chance.

Let’s plug in what we know.

Q = 76.0(2.22)(15.4)

Multiply.

Q = 2598.288

We want three significant figures.

Q = 2.60 •

or

Q = 2590 J

Hope this helps!

Answer:6,985.008

Explanation:

so the hear formula is mass times specific heat times change in temperature (kelvin) so what i did was got the change in temperature (41.4 K) and multiplied that times 2.22 J/(g•K)and multiplied that by 76 grams of Octane to get the Answer (not in scientific notation)