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PLEASE HELP ME WITH THIS ONE QUESTION One 10 Ohm resistor, R1, is connected to a 12 V battery. A second 10 Ohm resistor, R2, is added
Question
PLEASE HELP ME WITH THIS ONE QUESTION
One 10 Ohm resistor, R1, is connected to a 12 V battery. A second 10 Ohm resistor, R2, is added in series. What is the potential difference across each resistor?
A) R1 = 12 V and R2 = 0V
B) R1 = 6 V and R2 = 6V
C) R1 = 10 V and R2 = 2 V
D) R1 = 0 V and R2 = 12 V
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Physics
7 months
2021-08-09T07:06:01+00:00
2021-08-09T07:06:01+00:00 1 Answers
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Answer:
B) R1 = 6 V and R2 = 6V
Explanation:
In series, both resistors will carry the same current.
that current will be I = V/R = 12 / (10 + 10) = 0.6 A
The voltage drop across each resistor is V = IR = 0.6(10) = 6 V