PLEASE HELP ME SOLVE THIS!! PLZ Banpo Bridge fountain is 60 metres above the water. The water is projected with a horizontal spe

Question

PLEASE HELP ME SOLVE THIS!! PLZ
Banpo Bridge fountain is 60 metres above the water.
The water is projected with a horizontal speed of 6m/s
-Calculate:
1. The time taken to hit the river for a single droplet of water.
2. The range of the projectile for a single droplet of water.
3. The velocity (diagonal) when it hits the water.

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Philomena 1 year 2021-09-02T06:48:13+00:00 1 Answers 0 views 0

Answers ( )

  1. ngocdiep
    0
    2021-09-02T06:49:29+00:00
    Reply

    Answer:

    1.) Time = 3.5 seconds

    2.) Range = 21 m

    3.) Velocity = 34.8 m/s

    Explanation:

    Given that the

    Height h = 60 m

    Initial velocity U = 6 m/s

    1.) The time taken to hit the river for a single droplet of water can be achieved by using second equation of motion

    h = Ut + 1/2gt^2

    Let assume that the water drops from rest. Therefore, U = 0

    60 = 1/2 × 9.8t^2

    60 = 4.9t^2

    t^2 = 60/4.9

    t^2 = 12.24

    t = sqrt (12.24)

    t = 3.5s

    2.) The range of the projectile for a single droplet of water will be calculated by using the formula

    R = Ut

    Range R = 6 × 3.5 = 20.99

    Range = 21 m

    3.) The velocity (diagonal) when it hits the water.

    Using third equation of motion

    V^2 = U^2 + 2gH

    Substitute values into the equation

    V^2 = 6^2 + 2 × 9.8 × 60

    V^2 = 36 + 1176

    V^2 = 1212

    V = sqrt (1212)

    V = 34.8 m/s

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