Please help :) Kevin drops a 75 g “bouncy ball” out his second floor window, which is 8.0 m above the hard ground (pavement). He notic

Question

Please help 🙂
Kevin drops a 75 g “bouncy ball” out his second floor window, which is 8.0 m above the hard ground (pavement). He noticed that the ball bounced back up to a height of 6.1 m above the ground.

a) How much kinetic energy did the ball have just after it hit the ground (and bounced up again).

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niczorrrr 3 days 2021-07-22T11:02:39+00:00 1 Answers 1 views 0

Answers ( )

    0
    2021-07-22T11:04:30+00:00

    KE = 1/2mv^2

    1. Find velocity:
    8.0 + 6.1 = 14.1 m/s

    2. Plug and Chug
    KE = 1/2mv^2
    KE = 1/2(75g)(14.1 m/s)^2
    KE = 7,455.375 Joules

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