PLEASE HELP – In running a ballistics test at the police department, Officer Rios fires a 6.1g bullet at 350 m/s into a container that stops

Question

PLEASE HELP – In running a ballistics test at the police department, Officer Rios fires a 6.1g bullet at 350 m/s into a container that stops it in 0.32 min. What average force stops the bullet?​

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Thu Cúc 3 years 2021-09-04T20:05:44+00:00 2 Answers 0 views 0

Answers ( )

  1. huyenthanh
    0
    2021-09-04T20:06:53+00:00
    Reply

    Answer:

    –0.11 N.

    Explanation:

    Hope this helps

  2. kimchi2
    0
    2021-09-04T20:07:30+00:00
    Reply

    Answer:

    –0.11 N.

    Explanation:

    From the question given above, the following data were obtained:

    Mass (m) = 6.1 g

    Initial velocity (u) = 350 m/s

    Time (t) = 0.32 mins

    Final velocity (v) = 0 m/s

    Force (F) =?

    Next, we shall convert 0.32 mins to seconds. This can be obtained as follow:

    1 min = 60 s

    Therefore,

    0.32 mins = 0.32 × 60 = 19.2 s

    Next, we shall determine the acceleration of the the bullet. This can be obtained as follow:

    Initial velocity (u) = 350 m/s

    Time (t) = 19.2 s

    Final velocity (v) = 0 m/s

    v = u + at

    0 = 350 + (a × 19.2)

    0 = 350 + 19.2a

    Collect like terms

    0 – 350 = 19.2a

    –350 = 19.2a

    Divide both side by 19.2

    a = –350 / 19.2

    a = –18.23 m/s²

    Next, we shall convert 6.1 g to Kg.

    1000 g = 1 Kg

    Therefore,

    6.1 g = 6.1 g × 1 Kg / 1000 g

    6.1 g = 0.0061 Kg

    Finally, we shall determine the force. This can be obtained as follow:

    Mass (m) = 0.0061 Kg

    Acceleration (a) = –18.23 m/s²

    Force (F) =?

    F = ma

    F = 0.0061 × –18.23

    F = –0.11 N

    NOTE: The negative sign indicates that the force is in opposite direction.

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