PLEASE HELP I NEED HELP ASAP What is the equation of a line perpendicular to y=x+12 that passes through (12,3) ? I KNOW TH

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PLEASE HELP I NEED HELP ASAP
What is the equation of a line perpendicular to y=x+12 that passes through (12,3) ?

I KNOW THE STEPS BUT I NEED TO KNOW IF M = 1 in y=mx+b

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RI SƠ 4 years 2021-09-01T23:45:19+00:00 1 Answers 7 views 0

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  1. thuthuy
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    2021-09-01T23:46:32+00:00
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    Answer:

    y=-x+15

    Step-by-step explanation:

    Slope-intercept form is written as y=mx+b where m is the slope and b is the y-intercept.

    Any line perpendicular to a given line with slope m has a slope of -\frac{1}{m}. Therefore, the slope of a line perpendicular to y=x+12 is -\frac{1}{1}=-1.

    We can now plug the coordinate it passes through into our slope-intercept form equation to solve for the y-intercept:

    3=-1(12)+b,\\b=15

    Therefore, the equation of the line that is perpendicular to y=x+12 and passes through the coordinates (12,3) is \fbox{$y=-x+15$}.

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