Please help Asap! Solve for x and show your steps. Is the solution extraneous? Check your work to show how you determi

Question

Please help Asap!

Solve for x and show your steps. Is the solution extraneous? Check your work to show how you determined if the solution is extraneous or not.

The square root of the quantity 11 x plus 5 end quantity equals 7.

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Yến Oanh 3 weeks 2022-12-21T07:00:04+00:00 2 Answers 0 views 0

Answers ( 2 )

  1. thachthao
    0
    2022-12-21T07:01:45+00:00
    Reply
    Answer: x =4, not extraneous.
    Explanation:
    [tex]\sqrt{11x + 5} = 7[/tex], square all sides.
    Because the square root is squared, it is reversed: [tex]11x+5 =7^{2}[/tex]
    (72 = 49)
    Subtract 5 from all sides: 11x = 44
    (49 – 5 = 44)
    (11x is an unknown so we cannot subtract 5 from it)
    To get rid of the unknown, divide 11 on all sides: x = 4
    (11x ÷ 11 = 1, x is written as one) (44 ÷ 11 = 4)
    x = 4
    The solution is not extraneous.

  2. Edana
    0
    2022-12-21T07:01:49+00:00
    Reply
    Answer:
    Answer:
    Step-by-step explanation:
    \sqrt{11x+5}
    11x+5
    = 7 ( square both sides )
    11x + 5 = 7² = 49 ( subtract 5 from both sides )
    11x = 44 ( divide both sides by 11 )
    x = 4
    substitute x = 4 into the left side of the equation and if equal to the right side , then it is the solution.
    \sqrt{11(4)+5}
    11(4)+5
    = \sqrt{44+5}
    44+5
    = \sqrt{49}
    49
    = 7 ← equals right side
    then x = 4 is the solution

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