PLEASE HELP!!!!! An electron jumps from one energy level to another in an atom radiating 4.5*10^-19 Joules. If Planck’s constant is 6.63*10^

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PLEASE HELP!!!!! An electron jumps from one energy level to another in an atom radiating 4.5*10^-19 Joules. If Planck’s constant is 6.63*10^-34Js, what is the wavelength of the radiation? (C =3*10^8) 2)

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Kim Cúc 2 months 2021-09-01T08:03:08+00:00 1 Answers 0 views 0

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    2021-09-01T08:04:12+00:00

    Answer: λ = 4.42 × 10^-7 metres

    Explanation:

    The emitting radiation energy is the change in energy dE. Where

    dE = 4.5×10^-19J

    Planck’s constant h = 6.63*10^-34Js,

    Speed of light C = 3×10^8

    The wavelength(λ) of the radiation can be calculated by using the formula

    (λ) = hC/dE

    Substitute all the parameters into the formula above

    (λ) = (6.63×10^-34 × 3×10^8)/4.5×10^-19

    (λ) = 1.989^-25/4.5×10^-19

    (λ) = 4.42×10^-7 m

    Therefore, the wavelength (λ) of the radiation is 4.42 × 10^-7 metres

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