Please answer ASAP!! Cu+2 + 2e- ———> Cu E*= 0.52 V Ag+1 + 1e- ———> Ag E*= 0.80 V Using the two cell reduction

Question

Please answer ASAP!!
Cu+2 + 2e- ———> Cu E*= 0.52 V
Ag+1 + 1e- ———> Ag E*= 0.80 V

Using the two cell reduction potential shown for the corresponding reaction calculate the cell potential for a voltaic cell made from these two metals.
A. 1.32 V
B. -0.28 V
C.0.28 V
D. -1.32 V

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Thạch Thảo 2 months 2021-07-14T07:25:29+00:00 1 Answers 5 views 0

Answers ( )

    0
    2021-07-14T07:27:26+00:00

    Answer:

    C.0.28 V  

    Explanation:

    Using the standard cell potential we can find the standard cell potential for a voltaic cell as follows:

    The most positive potential is the potential that will be more easily reduced. The other reaction will be the oxidized one. That means for the reactions:

    Cu²⁺ + 2e⁻ → Cu E° = 0.52V

    Ag⁺ + 1e⁻ → Ag E° = 0.80V

    As the Cu will be oxidized:

    Cu → Cu²⁺ + 2e⁻

    The cell potential is:

    E°Cell = E°cathode(reduced) – E°cathode(oxidized)

    E°cell = 0.80V – (0.52V)

    E°cell = 1.32V

    Right answer is:

    C.0.28 V

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