## Ping lives at the corner of 3rd street and 6th avenue. ari lives at the corner of 21st street and 18th avenue. there is a gym two-

Question

Ping lives at the corner of 3rd street and 6th avenue. ari lives at the corner of 21st street and 18th avenue. there is a gym two-thirds the distance from ping’s home to ari’s home. x = (startfraction m over m n endfraction) (x 2 minus x 1) x 1 y = (startfraction m over m n endfraction) (y 2 minus y 1) y 1 where is the gym? 9th street and 10th avenue 12th street and 12th avenue 14th street and 12th avenue 15th street and 14th avenue

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7 days 2022-12-31T12:45:44+00:00 2 Answers 0 views 0

## Answers ( 2 )

1. The gym location is at 15th street, 14th Avenue.
We are given that:
Ping’s residence  = (3rd street, 6th Avenue)
Ari’s residence = (21st street, 18th Avenue)
Now, the distance between Ping’s and Ari’s home is:
Distance = (21st street, 18th Avenue) – (3rd street, 6th Avenue)
Distance = (18th , 12th )
Gym distance = 2/3 of distance between Ping’s home and Ari’s home
Gym distance = 2/3 × (18), 2/3 ×(12)
Gym distance = (12, 8)
Gym location = Ping’s home location +  the gym distance
= (3rd street, 6th Avenue) + (12th street, 8th Avenue)
= (15th street, 14th Avenue)
Therefore, the gym location is at 15th street, 14th Avenue.
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2. Answer:
Ping’s residence is at = (3rd street, 6th Avenue)
Ari’s residence is at = (21st street, 18th Avenue)
Gym location will be at = 2/3 the distance of Ping’s residence to Ari’s residence
So, distance between Ping’s home to Ari’s home
Distance will be = (21st street, 18th Avenue) – (3rd street, 6th Avenue)
Distance = (21 – 3) street, (18 – 6) avenue
Distance between ping and Ari = (18th , 12th )
Gym distance will be at = 2/3 of distance between ping and Ari
Gym distance = 2/3 × (18), 2/3 ×(12)
Gym distance = (12, 8)
Gym location will be at = Ping’s location + gym distance
Gym location will be at = (3rd street, 6th Avenue) + (12th street, 8th Avenue)
Gym location is = (15th street, 14th Avenue)
so the gym location is at 15th street, 14th Avenue.
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