per day of a certain industrial waste chemical arrives at a treatment plant settling pond with a volume of . is destroyed by sunlight, and o

Question

per day of a certain industrial waste chemical arrives at a treatment plant settling pond with a volume of . is destroyed by sunlight, and once in the pond it has a half-life of . Calculate the equilibrium concentration of in the pond. Round your answer to significant digits. g

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Ngọc Hoa 3 years 2021-07-17T02:47:46+00:00 1 Answers 149 views 0

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  1. thanhha
    0
    2021-07-17T02:49:44+00:00
    Reply

    The question is incomplete, the complete question is;

    49.9 g per day of a certain industrial waste chemical P arrives at a treatment plant settling pond with a volume of 300 m^3. P is destroyed by sunlight, and once in the pond it has a half-life of 3.4 h. Calculate the equilibrium concentration of P in the pond. Round your answer to 2 significant digits.

    Answer:

    0.034 g/m³

    Explanation:

    From the question, mass of industrial waste = 49.9 g

    It takes 24 hours to complete a day.

    Mass per hour;

    Mass in = (49.9 g / day) * (1 day /24 hr )

    = 2.079 g/hr

    Mass out = 0

    Mass leaving due to sunlight = k CA V

    Half life of the industrial waste = 3.4 h

    This is a first order reaction;

    Hence;

    k = ln2/t1/2

    Where, t1/2 = half life

    k = 0.693 / 3.4 = 0.2038 hr⁻¹

    Mass leaving due to sunlight = k CA V

    CA = Mass per hr / kV

    = 2.079 g/hr / ( 0.2038 hr⁻¹ x 300 m³ )

    = 0.034 g/m³

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